1x+0.06x^2=44

Solution for 1x+0.06x^2=44 equation:

1x+0.06x^2=44

We move all terms to the left:

1x+0.06x^2-(44)=0

We add all the numbers together, and all the variables

0.06x^2+x-44=0

a = 0.06; b = 1; c = -44;
Δ = b2-4ac
Δ = 12-4·0.06·(-44)
Δ = 11.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{11.56}}{2*0.06}=\frac{-1-\sqrt{11.56}}{0.12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{11.56}}{2*0.06}=\frac{-1+\sqrt{11.56}}{0.12}
$